https://file.aiquickdraw.com/mathbot/file/17289523736745eas25b6.jpg

To solve this problem, let's follow these steps:

Given dataTo solve this problem, let's follow these steps:

Given 
- Mass (\(M\)) of the object: \(8.92 \times 10^3\) tons
- Density (\(D\)) of the object: \(1.23 \times 10^{-2}\) tons per cubic foot
- Formula: \( D = \frac{M}{V} \), where \( V \) is the volume

We need to rearrange the formula to solve for \( V \):
\[
V = \frac{M}{D}
\]

### Step 1: Substitute the values
\[
V = \frac{8.92 \times 10^3}{1.23 \times 10^{-2}}
\]

### Step 2: Perform the calculation
To divide in scientific notation:
1. Divide the coefficients: \(\frac{8.92}{1.23} \approx 7.25\).
2. Subtract the exponents in the denominator from those in the numerator: \(10^3 - (-2) = 10^{3 + 2} = 10^5\).

Thus:
\[
V \approx 7.25 \times 10^5 \text{ cubic feet}
\]

### Final Answer:
The correct answer is **(A) \(7.25 \times 10^5\) cubic feet**.

Would you like more details on any part of the solution?

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### Related Questions
1. How would the answer change if the density was doubled?
2. Can this formula be used for liquids as well as solids?
3. How can we express answers in scientific notation when the exponent is negative?
4. What is the importance of rounding to the nearest hundredth in scientific notation?
5. How would we solve if mass was given in different units?

### Tip
When working with scientific notation, always align the exponents before performing addition or subtraction for more accurate calculations.

If the mass of an object is 8.92 × 10^3 tons and its density is 1.23 × 10^-2 tons per cubic foot, find the volume of the object. Use the formula D = M/V.

Learn how to calculate the volume of an object with a mass of 8.92 × 10^3 tons and a density of 1.23 × 10^-2 tons per cubic foot using scientific notation. This problem covers algebraic manipulation and properties of density, mass, and volume. Suitable for high school students in Grades 9-12.

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